document.write( "Question 719910: Please help. Thankyou. \r
\n" ); document.write( "\n" ); document.write( "An aquarium owner tested the chemical levels of the water in her 50 gallon tank. The water tested with a level of 2% of a certain chemical. She wanted to drop the level to a safe level of 1.25% How much of the aquarium water should be removed and pure water added to the aquarium?
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Algebra.Com's Answer #441585 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Let \"+x+\" = gallons of water to be removed and
\n" ); document.write( "replaced with pure water
\n" ); document.write( "The owner starts out with \"+.02%2A50+=+1+\" gallon of the chemical
\n" ); document.write( "The gallons of chemical that are removed when the water is drained
\n" ); document.write( "is \"+.02x+\"
\n" ); document.write( "Note that there are 50 gallons at the start and 50 gallons at the end
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\n" ); document.write( "\"+%28+1+-+.02x+%29+%2F+50+=+.0125+\"
\n" ); document.write( "\"+1+-+.02x+=+.0125%2A50+\"
\n" ); document.write( "\"+1+-+.02x+=+.625+\"
\n" ); document.write( "\"+.02x+=+1+-+.625+\"
\n" ); document.write( "\"+.02x+=+.375+\"
\n" ); document.write( "\"+x+=+18.75+\"
\n" ); document.write( "18.75 gallons should be drained and replaced with pure water
\n" ); document.write( "check:
\n" ); document.write( "\"+%28+1+-+.02%2A18.75+%29+%2F+50+=+.0125+\"
\n" ); document.write( "\"+%28+1+-+.375+%29+%2F+50+=+.0125+\"
\n" ); document.write( "\"+.625+%2F+50+=+.0125+\"
\n" ); document.write( "\"+.625+=+.625+\"
\n" ); document.write( "OK\r
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