document.write( "Question 63446This question is from textbook
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document.write( ": Carla invested $28,000, part at 14% and part at 16%. If the total interest at the end of the year is $4,160, how much did she invest at 14%? \n" );
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Algebra.Com's Answer #44157 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! .14X+.16(28,000-X)=4160 \n" ); document.write( ".14X+4480-.16X=4160 \n" ); document.write( "-.02X=4160-4480 \n" ); document.write( "-.02X=-320 \n" ); document.write( "X=-320/-.02 \n" ); document.write( "X=16,000 SOLUTION FOR 14% INVESTMENT. \n" ); document.write( " \n" ); document.write( " |