document.write( "Question 719842: Find the exact value of the following given the conditions, I was able to find cos (A+B):
\n" ); document.write( " $\"tanA=+-7%2F24+\"$ , $\"pi%2F2+%3C+A+%3C+pi\"$ ; $\"cosB=+5%2F6\"$ $\"0+%3C+B+%3C+pi%2F2\"$
\n" ); document.write( " $\"sin%28A%2BB%29\"$
\n" ); document.write( " $\"cos+%28A%2BB%29+=+%28-4%2F5%29+-%28%287sqrt%2811%29%29%2F150%29\"$
\n" ); document.write( " $\"sin%28A-B%29\"$
\n" ); document.write( " $\"tan%28A-B%29\"$
\n" ); document.write( " \n" ); document.write( "

Algebra.Com's Answer #441543 by jsmallt9(3758) $\"\"$ $\"About$

You can put this solution on YOUR website!
I'm not sure how you can figure out cos(A-B) but not the others. You must have figured out sin(A), sin(B) and cos(A) to figure out cos(A-B). Just use these same values in the formulas:
\n" ); document.write( "sin(A+B) = sin(A)cos(B) + cos(A)sin(B)
\n" ); document.write( "and
\n" ); document.write( "sin(A-B) = sin(A)cos(B) - cos(A)sin(B)

\n" ); document.write( " $\"tan%28A-B%29+=+%28tan%28A%29-tan%28B%29%29%2F%281%2Btan%28A%29tan%28B%29%29\"$
\n" ); document.write( "So we will need tan(A) and tan(B) to find tan(A-B). We were given tan(A). Using the same triangles you used to figure out the sin's and cos's of A and B we should be able to find tan(B):
\n" ); document.write( " $\"tan%28B%29+=+sqrt%2811%29%2F5\"$
\n" ); document.write( "Now just use these values in the tan(A-B) formula.
\n" ); document.write( " \n" ); document.write( "

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