document.write( "Question 719832: A 50% solution is added to a pure solution to get 40g of 60% solution/ How much pure solution is used. \n" ); document.write( "
Algebra.Com's Answer #441535 by stanbon(75887)\"\" \"About 
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A 50% solution is added to a pure solution to get 40g of 60% solution/ How much pure solution is used.
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\n" ); document.write( "Equation:
\n" ); document.write( "active + active = active
\n" ); document.write( "1*x + 0.50(40-x) = 0.60*40
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\n" ); document.write( "100x + 50*40-50x = 60*40
\n" ); document.write( "50x = 10*40
\n" ); document.write( "x = 8g (amt. of pure solution needed)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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