document.write( "Question 719832: A 50% solution is added to a pure solution to get 40g of 60% solution/ How much pure solution is used. \n" ); document.write( "
Algebra.Com's Answer #441535 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A 50% solution is added to a pure solution to get 40g of 60% solution/ How much pure solution is used. \n" ); document.write( "------ \n" ); document.write( "Equation: \n" ); document.write( "active + active = active \n" ); document.write( "1*x + 0.50(40-x) = 0.60*40 \n" ); document.write( "-------------------- \n" ); document.write( "100x + 50*40-50x = 60*40 \n" ); document.write( "50x = 10*40 \n" ); document.write( "x = 8g (amt. of pure solution needed) \n" ); document.write( "=============================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |