document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=719823>Question 719823</A>: <I><SPAN STYLE=\"word-break: break-all;\"> \r<BR>\n" );
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document.write( "Two complementary angles are in a ratio of 2 3. Find the measure of the larger angle<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #441528 by </B><A HREF=/tutors/aboutme.mpl?userid=lynnlo><B>lynnlo(4176)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lynnlo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=441528\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> PROBLEM================ratio of 2.3<BR>\n" );
document.write( "2x+3x=90======ADD 2+3==5<BR>\n" );
document.write( "5X=90<BR>\n" );
document.write( "X=18==WHEN YOU DIVIDE 90 BY 5 YOU GET=====18<BR>\n" );
document.write( "2X=36DEGREES======18X2=36<BR>\n" );
document.write( "3X=54DEGREES======18X3=54<BR>\n" );
document.write( "36 AND 54 DEGREES </SPAN>\n" );
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