document.write( "Question 719830: Can you help me solve this equation with substitution\r
\n" ); document.write( "\n" ); document.write( "-5x - 7y = -15
\n" ); document.write( "x + 2y = 6
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Algebra.Com's Answer #441523 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "\"-5x+-+7y+=+-15\"..eq.1
\n" ); document.write( "\"x+%2B+2y+=+6\"...eq.2
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\n" ); document.write( "start with \"x+%2B+2y+=+6\"...eq.2 and solve for \"x\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=+6-2y\"...eq.2a....substitute in eq.1\r
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\n" ); document.write( "\n" ); document.write( "\"-5%286-2y%29+-+7y+=+-15\"..eq.1...solve for \"y\"\r
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\n" ); document.write( "\n" ); document.write( "\"-30%2B10y+-7y+=+-15\"\r
\n" ); document.write( "\n" ); document.write( "\"3y+=+-15%2B30\"\r
\n" ); document.write( "\n" ); document.write( "\"3y+=+15\"\r
\n" ); document.write( "\n" ); document.write( "\"y+=+15%2F3\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28y+=+5%29\"...go back to eq.2a, substitute \"5\" for \"y\" and solve for \"x\"\r
\n" ); document.write( "\n" ); document.write( "\"x=+6-2%2A5\"...eq.2a\r
\n" ); document.write( "\n" ); document.write( "\"x=+6-10\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28x=+-4%29\"\r
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