document.write( "Question 719813: a. Jodie and Pedro are going to race each. Jodie can run 5yds , whereas Pedro can run 6 yds per second. Because she slower, Jodie also gets a head start of 13 yds. How far will Pedro have to run before he catches up to Jodie? How long will it take Pedro to catch up to Jodie? \n" ); document.write( "
Algebra.Com's Answer #441510 by josmiceli(19441)\"\" \"About 
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Let \"+d+\" = the distance in yds that Pedro has to run
\n" ); document.write( "in order to catch up with Jodie
\n" ); document.write( "\"+d+-+13+\" = the distance in yds that Jodie will run
\n" ); document.write( "until Pedro catches her
\n" ); document.write( "--------------------
\n" ); document.write( "Start a stopwatch when Pedro leaves.
\n" ); document.write( "Stop the stopwatch when Pedro catches her
\n" ); document.write( "Let \"+t+\" = the time on the stopwatch in seconds
\n" ); document.write( "--------------------
\n" ); document.write( "Jodie's equation:
\n" ); document.write( "(1) \"+d+-+13+=+5t+\"
\n" ); document.write( "Pedro's Equation:
\n" ); document.write( "(2) \"+d+=+6t+\"
\n" ); document.write( "---------------
\n" ); document.write( "By substitution:
\n" ); document.write( "(1) \"+6t+-+13+=+5t+\"
\n" ); document.write( "(1) \"+t+=+13+\"
\n" ); document.write( "-------------
\n" ); document.write( "(2) \"+d+=+6t+\"
\n" ); document.write( "(2) \"+d+=+6%2A13+\"
\n" ); document.write( "(2) \"+d+=+78+\"
\n" ); document.write( "and, also
\n" ); document.write( "(1) \"+d+-+13+=+5t+\"
\n" ); document.write( "(1) \"+d+-+13+=+5%2A13+\"
\n" ); document.write( "(1) \"+d+=+13+%2B+65+\"
\n" ); document.write( "(1) \"+d+=+78+\"
\n" ); document.write( "OK
\n" ); document.write( "----
\n" ); document.write( "Pedro has to run 78 yds to catch Jodie
\n" ); document.write( "It will take him 13 sec to catch her\r
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