document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=719762>Question 719762</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Why are the vertex, directrix, and focus of the parabola x^2-6x-8y+49=0 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #441498 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=441498\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Why are the vertex, directrix, and focus of the parabola x^2-6x-8y+49=0<BR>\n" );
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document.write( "Solve for \"y\":<BR>\n" );
document.write( "8y = x^2 -6x + 49<BR>\n" );
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document.write( "y = (1/8)x^2 - (3/4)x + (49/8)<BR>\n" );
document.write( "------<BR>\n" );
document.write( "Complete the square:<BR>\n" );
document.write( "y = (1/8)[x^2 - [(3/4)/(1/8)]x + ?] + (49/8) - (1/8)*?<BR>\n" );
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document.write( "y = (1/8)[x^2 - (6x) + 9] + (49/8)-(9/8)<BR>\n" );
document.write( "----<BR>\n" );
document.write( "y = (1/8)(x-3)^2 + 5<BR>\n" );
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document.write( "Vertex: (3,5)<BR>\n" );
document.write( "4p = 8<BR>\n" );
document.write( "p = 2<BR>\n" );
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document.write( "Focus: (3,7)<BR>\n" );
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document.write( "Directrix: y = 1<BR>\n" );
document.write( "======================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "====================== </SPAN>\n" );
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