document.write( "Question 719734: Hi,
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document.write( " My problem is:
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document.write( "The value of a two-digit number is twice as large as the sum of its digits. If the digits were reversed, the resulting number would be 9 less than 5 times the number. Find the original number.\r
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document.write( "Please explain in detail.
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document.write( "Thanks \n" );
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Algebra.Com's Answer #441485 by josgarithmetic(39617)![]() ![]() ![]() You can put this solution on YOUR website! X and Y are the digits. The number is \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "First condtion: \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Second condition, a bit complicated, but \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You should simplify each of those equations, and then solve for X and Y. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "First Condition: 10X+Y=2X+2Y, \n" ); document.write( ".. \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Second Condition: 10Y+X-5(10X+Y)=-9 \n" ); document.write( "10Y+X-50X-5Y=-9 \n" ); document.write( "-49X+5Y=-9 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "SYSTEM TO SOLVE: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "I tried solving both equations for y, equate them, and solve for the value of x... \n" ); document.write( "Number is 18. \n" ); document.write( " \n" ); document.write( " |