document.write( "Question 719734: Hi,
\n" ); document.write( " My problem is:
\n" ); document.write( "
\n" ); document.write( "The value of a two-digit number is twice as large as the sum of its digits. If the digits were reversed, the resulting number would be 9 less than 5 times the number. Find the original number.\r
\n" ); document.write( "\n" ); document.write( "Please explain in detail.
\n" ); document.write( "Thanks
\n" ); document.write( "

Algebra.Com's Answer #441485 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
X and Y are the digits. The number is \"10%2AX%2BY\", taking care of place value for this two digit number.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "First condtion: \"10X%2BY=2%28X%2BY%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Second condition, a bit complicated, but \"10Y%2BX=-9%2B5%2810X%2BY%29\". \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "You should simplify each of those equations, and then solve for X and Y. \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "First Condition: 10X+Y=2X+2Y,
\n" ); document.write( "..
\n" ); document.write( "\"8X-Y=0\"\r
\n" ); document.write( "\n" ); document.write( "Second Condition: 10Y+X-5(10X+Y)=-9
\n" ); document.write( "10Y+X-50X-5Y=-9
\n" ); document.write( "-49X+5Y=-9
\n" ); document.write( "\"49X-5Y=9\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "SYSTEM TO SOLVE:
\n" ); document.write( "\"highlight%2849X-5Y=9%29\"
\n" ); document.write( "\"highlight%288X-Y=0%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "I tried solving both equations for y, equate them, and solve for the value of x... \"highlight%28x-1%29\". Using that, 8*x-y=0, y=8*x, y=8*1, \"highlight%28y=8%29\".
\n" ); document.write( "Number is 18.
\n" ); document.write( "
\n" ); document.write( "
\n" );