document.write( "Question 719571: (y-3)/(y^2+y)-(y+1)/(2y)\r
\n" ); document.write( "\n" ); document.write( "Why is the answer:
\n" ); document.write( "-((y^2-7)/2y(y+1))\r
\n" ); document.write( "\n" ); document.write( "Because I was taught cross multiply for common denominator and so wouldn't it become, (2y)(y-3) - (y^2 + 1) (y+1) / (y^2+y)(2y)
\n" ); document.write( "Which then: 2y^2-6y - y^3+y^2+y+1 / 2y^2+2^2
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Algebra.Com's Answer #441464 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
Generally you cross multiply when you have an equal sign between single terms
\n" ); document.write( "Let's do it this way
\n" ); document.write( ":
\n" ); document.write( "\"%28y-3%29%2F%28y%5E2%2By%29\"-\"%28y%2B1%29%2F%282y%29\"
\n" ); document.write( "Factor out y in the 1st denominator
\n" ); document.write( "\"%28y-3%29%2F%28y%28y%2B1%29%29\"-\"%28y%2B1%29%2F%282y%29\"
\n" ); document.write( "the common denominator is 2y(y+1), so we have:
\n" ); document.write( "\"%282%28y-3%29+-+%28y%2B1%29%28y%2B1%29%29%2F%282y%28y%2B1%29%29\"
\n" ); document.write( "FOIL
\n" ); document.write( "\"%28%282y-6%29+-+%28y%5E2%2B2y%2B1%29%29%2F%282y%28y%2B1%29%29\"
\n" ); document.write( "removing brackets changes the signs
\n" ); document.write( "\"%28%282y+-+6+-+y%5E2+-+2y+-+1%29%29%2F%282y%28y%2B1%29%29\"
\n" ); document.write( "combine like terms
\n" ); document.write( "\"%28%28-y%5E2+-+7%29%29%2F%282y%28y%2B1%29%29\"
\n" ); document.write( " \n" ); document.write( "
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