document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=719654>Question 719654</A>: <I><SPAN STYLE=\"word-break: break-all;\"> You can ride a bike at 15 mph. Your sister rides 12 mph. You give her a one-hour head start. In how many hours will you catch up if neither of you stops.\r<BR>\n" );
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document.write( "(15 + x) (12 + x)<BR>\n" );
document.write( "15x - 12x\r<BR>\n" );
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document.write( "In 2 hours </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #441428 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=441428\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You can ride a bike at 15 mph. Your sister rides 12 mph. You give her a one-hour head start. In how many hours will you catch up if neither of you stops.\r<BR>\n" );
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document.write( "(15 + x) (12 + x)<BR>\n" );
document.write( "15x - 12x\r<BR>\n" );
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document.write( "In 2 hours<BR>\n" );
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document.write( "In 1 hour, she's 12 miles away (12*1)<BR>\n" );
document.write( "You \"gain on her\" at 3 mi/hr (15-12)<BR>\n" );
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document.write( "t = d/r = 12/3 = 4 hours </SPAN>\n" );
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