document.write( "Question 719654: You can ride a bike at 15 mph. Your sister rides 12 mph. You give her a one-hour head start. In how many hours will you catch up if neither of you stops.\r
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document.write( "(15 + x) (12 + x)
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document.write( "15x - 12x\r
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document.write( "In 2 hours \n" );
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Algebra.Com's Answer #441427 by stanbon(75887) ![]() You can put this solution on YOUR website! You can ride a bike at 15 mph. Your sister rides 12 mph. You give her a one-hour head start. In how many hours will you catch up if neither of you stops. \n" ); document.write( "---- \n" ); document.write( "Your DATA: \n" ); document.write( "rate = 15 mph ; time = x hrs ; distance = 15x miles \n" ); document.write( "-------- \n" ); document.write( "Sister DATA: \n" ); document.write( "rate = 12 mph ; time = x+1 hrs ; distance = 12(x+1) \n" ); document.write( "------ \n" ); document.write( "Equation: \n" ); document.write( "distance = distance \n" ); document.write( "15x = 12x + 12 \n" ); document.write( "3x = 12 \n" ); document.write( "x = 4 hrs (time to catch up) \n" ); document.write( "------------------------ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "======================== \n" ); document.write( " |