document.write( "Question 719654: You can ride a bike at 15 mph. Your sister rides 12 mph. You give her a one-hour head start. In how many hours will you catch up if neither of you stops.\r
\n" ); document.write( "\n" ); document.write( "(15 + x) (12 + x)
\n" ); document.write( "15x - 12x\r
\n" ); document.write( "\n" ); document.write( "In 2 hours
\n" ); document.write( "

Algebra.Com's Answer #441427 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
You can ride a bike at 15 mph. Your sister rides 12 mph. You give her a one-hour head start. In how many hours will you catch up if neither of you stops.
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\n" ); document.write( "Your DATA:
\n" ); document.write( "rate = 15 mph ; time = x hrs ; distance = 15x miles
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\n" ); document.write( "Sister DATA:
\n" ); document.write( "rate = 12 mph ; time = x+1 hrs ; distance = 12(x+1)
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\n" ); document.write( "Equation:
\n" ); document.write( "distance = distance
\n" ); document.write( "15x = 12x + 12
\n" ); document.write( "3x = 12
\n" ); document.write( "x = 4 hrs (time to catch up)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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