document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=8045>Question 8045</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A sum of Rs. 500 is in the form of denominations of Rs. 5 and 10. If total no. of notes is 90, find no. of each type of note.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #4414 by </B><A HREF=/tutors/aboutme.mpl?userid=gokhalesujata><B>gokhalesujata(4)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=gokhalesujata><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=4414\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x be the number of notes of denomination Rs5<BR>\n" );
document.write( "Let y be the number of notes of denomination Rs10<BR>\n" );
document.write( "we know that the total amount is Rs500 which means 5 times the number of notes of denom Rs5 + 10 times the number of notes of denomination Rs 10 equals 500<BR>\n" );
document.write( "ie. 5x+10y=500<BR>\n" );
document.write( "Also total number of notes is 90 ie x+y=90<BR>\n" );
document.write( "hence x=90-y<BR>\n" );
document.write( "5*(90-y)+10y=500<BR>\n" );
document.write( "450-5y+10y=500<BR>\n" );
document.write( "5y=500-450<BR>\n" );
document.write( "5y=50<BR>\n" );
document.write( "y=50/5<BR>\n" );
document.write( "y=10<BR>\n" );
document.write( "x=90-y=90-10=80<BR>\n" );
document.write( "hence 10 notes of Rs10 and 80 notes of Rs5<BR>\n" );
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