document.write( "Question 719353: a chemist has three different acid solutions. The first acid solution contains 20% acid, the second contains 30% and the third contains 75%. He wants to use all three solutions to obtain a mixture of 68 liters containing 50% acid, using 2 times as much of the 75% solution as the 30% solution. how many liters of each solution should be used? \n" ); document.write( "
Algebra.Com's Answer #441368 by josgarithmetic(39618)![]() ![]() ![]() You can put this solution on YOUR website! Let x amount of 20% acid \n" ); document.write( "let y amount of 30% acid \n" ); document.write( "let z amount of 75% acid\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "\"using 2 times as much of the 75% solution as the 30% solution. \", \n" ); document.write( "That means z/y=2/1 or \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Two essential starting equations: \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The less advanced way to solve this is to begin with the ratio between z and y and substitute into the \"two essential\" equations:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The percentage equation: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The solution summation equation: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Our simpler system to solve is now in variables x and y: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Subtract the second from the first, and from resulting 6y=102, obtain \n" ); document.write( "Use that result again in the second equation, x=68-3y, x=68-3*17, \n" ); document.write( "\n" ); document.write( "Now, go back to the given relationship between z and y, z=2y, z=2*17, \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "ANSWER SUMMARY: x=17 liters of 20%, y=17 liters of 30%, z=34 liters of 75% acid. \n" ); document.write( " |