document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=719502>Question 719502</A>: <I><SPAN STYLE=\"word-break: break-all;\"> two cars leave town at the same time going in the same direction on the same road. One travels 30 mi/h and the other travels 46 mi/h. If they both start at 2:00 pm, when will they be 76 miles apart? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #441365 by </B><A HREF=/tutors/aboutme.mpl?userid=graphmatics><B>graphmatics(170)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=graphmatics><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=graphmatics><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=441365\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let t be the time in hours that the 2 cars travel. Then at the time the cars are 76 miles apart the cars will have traveled 46*t and 30*t. If they are 76 miles apart then<BR>\n" );
document.write( "46t-30t=76<BR>\n" );
document.write( "So<BR>\n" );
document.write( "16*t=76<BR>\n" );
document.write( "t=76/16<BR>\n" );
document.write( "t=4.75<BR>\n" );
document.write( "So it takes 4.75 hours for the cars to be 76 miles apart. .75% of an hour is 45 minutes, so the time they will be 76 miles apart is 6:45. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );