document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=719497>Question 719497</A>: <I><SPAN STYLE=\"word-break: break-all;\"> write equation that has a slope of -2/3 and contains (-6,-4).<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #441364 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=441364\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> m=slope=-2/3\r<BR>\n" );
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document.write( "point(-6,-4)\r<BR>\n" );
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document.write( "equation in slope point form\r<BR>\n" );
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document.write( "(y-y1)=m(x-x1) Where (x1,y1) are the coordinates and m is the slope<BR>\n" );
document.write( "substitute\r<BR>\n" );
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document.write( "y-(-4)=(-2/3)(x-(-6))\r<BR>\n" );
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document.write( "y+4 = (-2/3)x  -4\r<BR>\n" );
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document.write( "multiply equation by 3\r<BR>\n" );
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document.write( "3y+12= -2x-12\r<BR>\n" );
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document.write( "3y=-12-2x-12\r<BR>\n" );
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document.write( "3y=-2x-24\r<BR>\n" );
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document.write( "y=(-2/3)x -8 </SPAN>\n" );
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