document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=719446>Question 719446</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 6*a+2*a^3-2-10*a^2\r<BR>\n" );
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document.write( "I have to factor the polynomial but it is not making sense. I found gcf  and worked it to 2(3*a+a^3)-(1-5*a^2) I'm not sure what to do from here.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #441360 by </B><A HREF=/tutors/aboutme.mpl?userid=graphmatics><B>graphmatics(170)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=graphmatics><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=graphmatics><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=441360\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You almost have it. We note that each part of the given expression has a 2 AND an a as a factor so first factor out the 2 to get<BR>\n" );
document.write( "6*a+2*a^3-2-10*a^2 = 2*(3*a+a^3-1-5*a^2)<BR>\n" );
document.write( "put the right side the reducing order to get<BR>\n" );
document.write( "6*a+2*a^3-2-10*a^2=2*(a^3-5*a^2+3*a-1)<BR>\n" );
document.write( "                  =2*(a^2-4*a+1)*(a-1)<BR>\n" );
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