document.write( "Question 719374: A FATHER IS NOW 7 TIMES AS OLD AS HIS SON. IN 5 YEARS, HE WILL BE 4 TIMES AS OLD AS HIS SON WILL BE THEN. WHAT ARE THEIR PRESENT AGES? \n" ); document.write( "
Algebra.Com's Answer #441334 by mathworm7271(5)\"\" \"About 
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Let's call the fathers age f and the sons age s.
\n" ); document.write( "Write out the formulas.
\n" ); document.write( "F=7S
\n" ); document.write( "F+5=4(S+5)
\n" ); document.write( "Use the Distributive property on the 2nd equation
\n" ); document.write( "F+5=4S+20
\n" ); document.write( "Subtract 5 from both sides
\n" ); document.write( "F=4S+15
\n" ); document.write( "Now substitute
\n" ); document.write( "7S=4S+15
\n" ); document.write( "Subtract 4S from both sides
\n" ); document.write( "3S=15
\n" ); document.write( "Divide both sides by three
\n" ); document.write( "S=5
\n" ); document.write( "Plug in S to the first equation
\n" ); document.write( "F=7(5)=35
\n" ); document.write( "Therefore, the Father's age is 35 and the Son's age is 7
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