document.write( "Question 719374: A FATHER IS NOW 7 TIMES AS OLD AS HIS SON. IN 5 YEARS, HE WILL BE 4 TIMES AS OLD AS HIS SON WILL BE THEN. WHAT ARE THEIR PRESENT AGES? \n" ); document.write( "
Algebra.Com's Answer #441334 by mathworm7271(5)![]() ![]() You can put this solution on YOUR website! Let's call the fathers age f and the sons age s. \n" ); document.write( "Write out the formulas. \n" ); document.write( "F=7S \n" ); document.write( "F+5=4(S+5) \n" ); document.write( "Use the Distributive property on the 2nd equation \n" ); document.write( "F+5=4S+20 \n" ); document.write( "Subtract 5 from both sides \n" ); document.write( "F=4S+15 \n" ); document.write( "Now substitute \n" ); document.write( "7S=4S+15 \n" ); document.write( "Subtract 4S from both sides \n" ); document.write( "3S=15 \n" ); document.write( "Divide both sides by three \n" ); document.write( "S=5 \n" ); document.write( "Plug in S to the first equation \n" ); document.write( "F=7(5)=35 \n" ); document.write( "Therefore, the Father's age is 35 and the Son's age is 7 \n" ); document.write( " |