document.write( "Question 719299: a man invests one sum of money at 5% and a second sum, $2000 greater than the first sum at 6%. After one year his total income from investments is $1000. \n" ); document.write( "
Algebra.Com's Answer #441301 by checkley79(3341) ![]() You can put this solution on YOUR website! .05x+.06(x+2,000)=1,000 \n" ); document.write( ".05x+.06x+120=1,000 \n" ); document.write( ",11x=1,000-120 \n" ); document.write( ".1x=880 \n" ); document.write( "x=880/.11 \n" ); document.write( "x=$8,000 invested @ 6%. \n" ); document.write( "8,000+2,000=$10,000 invested @ 6% \n" ); document.write( "Proof: \n" ); document.write( ".05*8,000+.06*10,000=1000 \n" ); document.write( "400+600=$1,000 \n" ); document.write( " |