document.write( "Question 719299: a man invests one sum of money at 5% and a second sum, $2000 greater than the first sum at 6%. After one year his total income from investments is $1000. \n" ); document.write( "
Algebra.Com's Answer #441301 by checkley79(3341)\"\" \"About 
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.05x+.06(x+2,000)=1,000
\n" ); document.write( ".05x+.06x+120=1,000
\n" ); document.write( ",11x=1,000-120
\n" ); document.write( ".1x=880
\n" ); document.write( "x=880/.11
\n" ); document.write( "x=$8,000 invested @ 6%.
\n" ); document.write( "8,000+2,000=$10,000 invested @ 6%
\n" ); document.write( "Proof:
\n" ); document.write( ".05*8,000+.06*10,000=1000
\n" ); document.write( "400+600=$1,000
\n" ); document.write( "
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