document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=8046>Question 8046</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 5 years ago, a man was 7 times as old as his son. 5years hence, father will be 3 times as old as his son. Find their present ages.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #4413 by </B><A HREF=/tutors/aboutme.mpl?userid=gokhalesujata><B>gokhalesujata(4)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=gokhalesujata><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=4413\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Sons age 5 years ago=x father's age = 7x<BR>\n" );
document.write( "their present age = x+5 and 7x+5 resp<BR>\n" );
document.write( "Sons age 5 years hence = x+10(since x is sons age 5 years ago from present age and we are talking of his age 5 years hence from his present age so 5+5=10)<BR>\n" );
document.write( "fathers age 5 years hence =3(x+10)<BR>\n" );
document.write( "hence the fathers present age will be 3(x+10)-5<BR>\n" );
document.write( "also fathers present age =7x+5<BR>\n" );
document.write( "therefore 7x+5=3(x+10)-5<BR>\n" );
document.write( "7x+5=3x+30-5<BR>\n" );
document.write( "7x-3x=25-5<BR>\n" );
document.write( "4x=20<BR>\n" );
document.write( "x=5<BR>\n" );
document.write( "sons age 5 years ago=5years fathers age =5*7=35years<BR>\n" );
document.write( "present age of the son=10years(5+5) fathers age=35+5=40 years<BR>\n" );
document.write( "sons age 5 years hence= 5+10=15years fathers age =3*(5+10)=45 years </SPAN>\n" );
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