document.write( "Question 719291: Hello. I have the following trigonometric question to answer but im stuck. Please note the B in the equation is Beta. Solve the following for between 0 and 360 degrees: .\r
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document.write( "I have done the following: 3-2sinB + 12sinB - 8sin^2B = 2, which then goes to -8sin^2B + 10sinB +1 = 0\r
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document.write( "Is my next step to transform this into a quadratic equation? and then work out both sections individually as equalling zero?\r
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document.write( "Any advice would be great. Thanks! \n" );
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Algebra.Com's Answer #441296 by stanbon(75887) ![]() You can put this solution on YOUR website! Solve the following for B between 0 and 360 degrees: \n" ); document.write( "(1+4 sin B)(3-2 sin B)=2 \n" ); document.write( "----- \n" ); document.write( "Let x = sin(B) \n" ); document.write( "----- \n" ); document.write( "(1+4x)(3-2x) = 2 \n" ); document.write( "3 + 10x - 8x^2 = 2 \n" ); document.write( "--- \n" ); document.write( "8x^2 -10x - 1 = 0 \n" ); document.write( "----- \n" ); document.write( "x = [10 +- sqrt(100-4*8*-1)]/16 \n" ); document.write( "---- \n" ); document.write( "x = [10 +- sqrt(132)]/16 \n" ); document.write( "---- \n" ); document.write( "Usable solution: \n" ); document.write( "x = -0.0931 \n" ); document.write( "----- \n" ); document.write( "Solve for \"B\" \n" ); document.write( "sin(B) = -0.0931 \n" ); document.write( "B = sin^-1(-0.0931) = 354.66 degrees or B = 185.34 degrees \n" ); document.write( "============================================================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "================== \n" ); document.write( " |