document.write( "Question 719218: Hi\r
\n" ); document.write( "\n" ); document.write( "\"+%28-%28x-1%29%5E2%282-x%29%29%2F%28%283-x%29%285x-1%29%5E2%29%3E=0+\"\r
\n" ); document.write( "\n" ); document.write( "It would be very nice to have explanations too.
\n" ); document.write( "Thanks,
\n" ); document.write( "Richard
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Algebra.Com's Answer #441254 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
(-(x-1)^2(2-x))/((3-x)(5x-1)^2) >= 0
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\n" ); document.write( "1st: Solve the EQUALITY:
\n" ); document.write( "-(x-1)^2(2-x) = 0
\n" ); document.write( "x = 1 or x = 2
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\n" ); document.write( "2nd: Note value that x cannot take:
\n" ); document.write( "x = 3 or x = 1/5
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\n" ); document.write( "3rd: Solve the INEQUALITY:
\n" ); document.write( "Draw a number line and plot x = 1/5, x = 1, x = 2, x = 3
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\n" ); document.write( "Test a value in each of the resulting 5 number line intervals
\n" ); document.write( "to find solution intervals:
\n" ); document.write( "(-(x-1)^2(2-x))/((3-x)(5x-1)^2) > 0
\n" ); document.write( "If x=0 you get: [-(-1)^2(2)]/[(3*(-1)^2] = -2/3 is not > 0
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\n" ); document.write( "If x=1/2 you get: [-(-1/2)^2(3/2)]/[(5/2)(3/2)^2] = (-3/8)/+ is not > 0
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\n" ); document.write( "If x = 3/2 the result is not > 0
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\n" ); document.write( "If x = 5/2 the result IS > 0
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\n" ); document.write( "If x = 10 the result is not > 0
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\n" ); document.write( "Conclusion:
\n" ); document.write( "Solution: x = 1 or values in the interval [2,3)
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\n" ); document.write( "\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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