document.write( "Question 63146: THE POLYNOMIAL f(x) DIVIDED x-3 RESULTS IN A QUOTIENT OF x2+3x-5 WITH A REMAINDER OF 2. FIND f(3). \n" ); document.write( "

Algebra.Com's Answer #44119 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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THE POLYNOMIAL f(x) DIVIDED x-3 RESULTS IN A QUOTIENT OF x2+3x-5 WITH A REMAINDER OF 2. FIND f(3).
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\n" ); document.write( "The problem as I understand it:
\n" ); document.write( " $\"f%28x%29%2F%28x-3%29\"$ = x^2 + 3x - 5, Remainder of 2/(x-3)
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\n" ); document.write( "Find f(x)
\n" ); document.write( "f(x) = (x-3) * (x^2 + 3x - 5)
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\n" ); document.write( "Used \"....\" to keep things lined up
\n" ); document.write( "...........x^2 + 3x - 5
\n" ); document.write( "........................x - 3
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\n" ); document.write( ".........-3x^2 - 9x + 15
\n" ); document.write( "x^3 + 3x^2 - 5x
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\n" ); document.write( "x^3 + 0x^2 -14x + 15
\n" ); document.write( "add remainder.......+ 2
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\n" ); document.write( "..........x^3 - 14x + 17 = f(x)
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\n" ); document.write( "Find f(3)
\n" ); document.write( "f(3) = 3^3 - 14(3) + 17
\n" ); document.write( "f(3) = 27 - 42 + 17
\n" ); document.write( "f(3) = 2
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