document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=718949>Question 718949</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the measure of angle 1= 4x+3 and the measure of angle 2=3x+8, find x so that angle 1 is supplementary to angle 2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #441189 by </B><A HREF=/tutors/aboutme.mpl?userid=jsmallt9><B>jsmallt9(3758)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jsmallt9><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=441189\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Two angles are supplementary if their measures add up to 180. So:<BR>\n" );
document.write( "(4x+3) + (3x+8) = 180<BR>\n" );
document.write( "Now we solve for x:<BR>\n" );
document.write( "7x + 11 = 180<BR>\n" );
document.write( "7x = 169<BR>\n" );
document.write( "x = 169/11 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );