document.write( "Question 718743:
\n" ); document.write( "If 5 times the smaller of two numbers is subtracted from twice the larger, the result is 16. If the larger is increased by 3 times the smaller, the result is 63. Find the numbers.
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Algebra.Com's Answer #441048 by checkley79(3341)\"\" \"About 
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LET X BE THE SMALLER & Y BE THE LARGER NUMBER.
\n" ); document.write( "2Y-5X=16
\n" ); document.write( "3X+Y=63 OR Y=63-3X
\n" ); document.write( "2(63-3X)-5X=16
\n" ); document.write( "126-6X-5X=16
\n" ); document.write( "-11X=16-126
\n" ); document.write( "-11X=-110
\n" ); document.write( "X=-110/-11
\n" ); document.write( "X=10 ANS. FOR THE SMALLER NUMBER.
\n" ); document.write( "Y=63-3*10
\n" ); document.write( "Y=63-30
\n" ); document.write( "Y=33 ANS. FOR THE LARGER NUMBER.
\n" ); document.write( "PROOF:
\n" ); document.write( "3*10+33=63
\n" ); document.write( "30+33=63
\n" ); document.write( "63=63
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