document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=718629>Question 718629</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Willie invests 10,000 at 8 and 1/2%, how much additional money must he invest at 7% so that his total annual income from these investments may equal 8% of the principal </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #441021 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=441021\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Willie invests 10,000 at 8 and 1/2%, how much additional money must he invest at 7% so that his total annual income from these investments may equal 8% of the principal<BR>\n" );
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document.write( "Let x = amt of money at 7% required to accomplish this<BR>\n" );
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document.write( ".085(10000) + .07x = .08(x+10000) <BR>\n" );
document.write( "850 + .07x = .08x + 800<BR>\n" );
document.write( "850 - 800 = .08x - .07x<BR>\n" );
document.write( "50 = .01x<BR>\n" );
document.write( "x = 50/.01<BR>\n" );
document.write( "x = $5000 additional $ invested at 7% </SPAN>\n" );
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