document.write( "Question 63367: There are three consectutive integers such that 8 more than twice the 2nd integer is three times the sum of the 1st and 3rd integer. Find the three integers.\r
\n" ); document.write( "\n" ); document.write( "Whomever this may concern, I needed to know if my calculations were correct?\r
\n" ); document.write( "\n" ); document.write( "x
\n" ); document.write( "x + 2
\n" ); document.write( "x + 3\r
\n" ); document.write( "\n" ); document.write( "8 + 2 (x+2) = 3 (x+x+3)
\n" ); document.write( "8x + 2x + 4 = 6x + 9
\n" ); document.write( "2x + 12 = 6x + 9\r
\n" ); document.write( "\n" ); document.write( "I then subtract 9 from both sides\r
\n" ); document.write( "\n" ); document.write( "2x + 3 = 6x\r
\n" ); document.write( "\n" ); document.write( "I then subtract 2x from both sides\r
\n" ); document.write( "\n" ); document.write( "+ 3 = 4x\r
\n" ); document.write( "\n" ); document.write( "Our teacher provides an answer sheet with our review worksheet. Her answers were 1, 2, and 3.\r
\n" ); document.write( "\n" ); document.write( "This is where I am lost; I get 0.75 when I divide 3/4\r
\n" ); document.write( "\n" ); document.write( "Thanks for your time. \n" ); document.write( "

Algebra.Com's Answer #44098 by 303795(602) $\"\"$ $\"About$

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Your consecutive integers need to be x, (x + 1) and (x + 2).\r
\n" ); document.write( "\n" ); document.write( "The method used seems sound although you ended up with an 8x which should just be an 8 at one stage.
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