document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=718532>Question 718532</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The distance between Hazleton and Pleasantville is 100miles. At 2:00 p.m. Mike starts riding his bicycle from Hazleton to Pleasantville at a constant speed of 18 mi/h. Twenty minutes later Katie leaves Hazleton for Pleasantville traveling at a rate of 30 mi/h. How far from Pleasantville are they when Katie catches up with Mike? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #440934 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=440934\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the distance from Hazelton when they meet be x<BR>\n" );
document.write( "Let time taken by Mike be y<BR>\n" );
document.write( "speed mike =18m/h\r<BR>\n" );
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document.write( "Distance = speed * time\r<BR>\n" );
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document.write( "x= 18y\r<BR>\n" );
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document.write( "Katie speed = 30m/h<BR>\n" );
document.write( "time = y-(1/3) hours\r<BR>\n" );
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document.write( "distance =x<BR>\n" );
document.write( "x= (y-1/3) *30<BR>\n" );
document.write( "=((3y-1)/3 )*30\r<BR>\n" );
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document.write( "equate both\r<BR>\n" );
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document.write( "18y=30y-10\r<BR>\n" );
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document.write( "-12y= -10\r<BR>\n" );
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document.write( "y= 5/6 hours\r<BR>\n" );
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document.write( "So Mike takes 5/6 hours\r<BR>\n" );
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document.write( "x=18y<BR>\n" );
document.write( "x= 18*5/6<BR>\n" );
document.write( "=15 miles\r<BR>\n" );
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document.write( "so they are 100-15 = 85 miles from Pleasantville\r<BR>\n" );
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document.write( " </SPAN>\n" );
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