document.write( "Question 718466: a designer invest $20,000.0 in two CDs. the first CD pays 11% per annum simple interest, and the second pays 12.5%. at the end of on year she has earned 2320.0 in interest. \r
\n" ); document.write( "\n" ); document.write( "* how much did she invest in each CD?\r
\n" ); document.write( "\n" ); document.write( "* what was the effective interest rate on the total investments?
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Algebra.Com's Answer #440911 by mananth(16946)\"\" \"About 
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CD I 11.00% per annum ------------- Amount invested =x
\n" ); document.write( "CD II 12.50% per annum ------------ Amount invested = y
\n" ); document.write( " 20000
\n" ); document.write( "Interest----- 2320
\n" ); document.write( "
\n" ); document.write( "CD I 11.00% per annum ---x
\n" ); document.write( "CD II 12.50% per annum ---y
\n" ); document.write( "Total investment
\n" ); document.write( "x + 1 y= 20000 -------------1
\n" ); document.write( "Interest on both investments
\n" ); document.write( "11.00% x + 12.50% y= 2320
\n" ); document.write( "Multiply by 100
\n" ); document.write( "11 x + 12.5 y= 232000.00 --------2
\n" ); document.write( "Multiply (1) by -11
\n" ); document.write( "we get
\n" ); document.write( "-11 x -11 y= -220000.00
\n" ); document.write( "Add this to (2)
\n" ); document.write( "0 x 1.5 y= 12000
\n" ); document.write( "divide by 1.5
\n" ); document.write( " y = 8000
\n" ); document.write( "CD I 11.00% $ 12000
\n" ); document.write( "CD II 12.50% $ 8000
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\n" ); document.write( "CHECK
\n" ); document.write( "12000 --------- 11.00% ------- 1320.00
\n" ); document.write( "8000 ------------- 12.50% ------- 1000.00
\n" ); document.write( "Total -------------------- 2320.00 \r
\n" ); document.write( "\n" ); document.write( "20000----------2320
\n" ); document.write( "100----------?\r
\n" ); document.write( "\n" ); document.write( "100/20000 * 2320
\n" ); document.write( "
\n" ); document.write( "11.6%
\n" ); document.write( "m.ananth@hotmail.ca
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