document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=718170>Question 718170</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am having problems figuring out linear equations i dont really know where to start x+y=3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #440790 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley79><B>checkley79(3341)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley79><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=440790\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Y=mX+b IS THE STANDARD LINER EQUATION WHERE m=THE LINE SLOPE & b=THE Y INTERCEPT.<BR>\n" );
document.write( "x+y=3<BR>\n" );
document.write( "Y=-X+3 HERE YOU HAVE A LINE WITH SLOPE=-1 & THE Y INTERCEPT=3.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+graph%28+300%2C+200%2C+-6%2C+5%2C+-5%2C+5%2C+-x+%2B3%29+ ALIGN=MIDDLE  ALT=\"+graph%28+300%2C+200%2C+-6%2C+5%2C+-5%2C+5%2C+-x+%2B3%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );