document.write( "Question 718082: Find the equation of the line tangent to the given circle and passing through the given point
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document.write( "1. x^2+y^2= 26 (4,6) \n" );
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Algebra.Com's Answer #440769 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! Find the equation of the line tangent to the given circle and passing through the given point \n" ); document.write( "1. x^2+y^2= 26 (4,6) \n" ); document.write( "--------------------------- \n" ); document.write( "There are 2 tangent lines thru the point. \n" ); document.write( "The point, the tangent points and the center make right triangles. \n" ); document.write( "--- \n" ); document.write( "Find the distance from the point to the center of the circle \n" ); document.write( "d = sqrt(52) = the hypotenuse \n" ); document.write( "The radius is one side of the triangle, length = sqrt(26) \n" ); document.write( "Use Pythagoras to find the distance from the point to the \n" ); document.write( "tangent points, = sqrt(26) \n" ); document.write( "-------------- \n" ); document.write( "The tangent points are the intersections of the given circle and a circle of radius sqrt(26) centered at (4,6) \n" ); document.write( "------------- \n" ); document.write( "Find the 2 intersections. \n" ); document.write( "---- \n" ); document.write( "The 2 lines are the lines thru the tangent point and (4,6) \n" ); document.write( "================= \n" ); document.write( "email via the Thank You note for help, or to check your work. \n" ); document.write( " \n" ); document.write( " |