document.write( "Question 718117: mary has 54 coins which are either 20-cent coins or 50-cent coins.If the total amount is $20.70, how many 20-cent coins does Mary have? \n" ); document.write( "
Algebra.Com's Answer #440753 by checkley79(3341)![]() ![]() ![]() You can put this solution on YOUR website! X+Y=54 \n" ); document.write( "X=54-Y \n" ); document.write( ".20X+.50Y=20.70 \n" ); document.write( ".20(54-Y)+.50Y=20.70 \n" ); document.write( "10.80-.20Y+.50Y=20.70 \n" ); document.write( ".30Y=20.70-10.80 \n" ); document.write( ".30Y=9.90 \n" ); document.write( "Y=9.90/.30 \n" ); document.write( "Y=33 50-CENT COINS. \n" ); document.write( "X+33=54 \n" ); document.write( "X=54-33 \n" ); document.write( "X=21 20-CENT COINS. \n" ); document.write( "PROOF: \n" ); document.write( ".20*21+.50*33=20.70 \n" ); document.write( "4.20+16.50=20-70 \n" ); document.write( "20.70=20.70 \n" ); document.write( " \n" ); document.write( " |