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document.write( "Ahmad is twice as old as Bobby. John is 7 years younger than Ahmad. If the sum of their ages is 38, how old are the three boys? \n" );
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Algebra.Com's Answer #440748 by checkley79(3341)![]() ![]() ![]() You can put this solution on YOUR website! A=2B \n" ); document.write( "J=A-7 OR 2B-7 \n" ); document.write( "A+B+J=38 \n" ); document.write( "(2B)+B+(2B-7)=38 \n" ); document.write( "5B-7=38 \n" ); document.write( "5B=38=7 \n" ); document.write( "5B=45 \n" ); document.write( "B=45/5 \n" ); document.write( "B=9 AGE OF BOBBY. \n" ); document.write( "A=2*9=18 AGE OF AHMAD. \n" ); document.write( "J=18-7=11 AGE OF JOHN. \n" ); document.write( "PROOF: \n" ); document.write( "18+9+11=38 \n" ); document.write( "38=38 \n" ); document.write( " \n" ); document.write( " |