document.write( "Question 718118: \r
\n" ); document.write( "\n" ); document.write( "Ahmad is twice as old as Bobby. John is 7 years younger than Ahmad. If the sum of their ages is 38, how old are the three boys?
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Algebra.Com's Answer #440748 by checkley79(3341)\"\" \"About 
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A=2B
\n" ); document.write( "J=A-7 OR 2B-7
\n" ); document.write( "A+B+J=38
\n" ); document.write( "(2B)+B+(2B-7)=38
\n" ); document.write( "5B-7=38
\n" ); document.write( "5B=38=7
\n" ); document.write( "5B=45
\n" ); document.write( "B=45/5
\n" ); document.write( "B=9 AGE OF BOBBY.
\n" ); document.write( "A=2*9=18 AGE OF AHMAD.
\n" ); document.write( "J=18-7=11 AGE OF JOHN.
\n" ); document.write( "PROOF:
\n" ); document.write( "18+9+11=38
\n" ); document.write( "38=38
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