document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=718062>Question 718062</A>: <I><SPAN STYLE=\"word-break: break-all;\"> \r<BR>\n" );
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document.write( "Rectangle has perimeter of 490mm, lengths sides are the ratio 3:4, the dimensions of the rectangle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #440742 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley79><B>checkley79(3341)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley79><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=440742\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> LET THE LENGTH BE 3X & THE WIDTH BE 4X<BR>\n" );
document.write( "P=2L+2W<BR>\n" );
document.write( "490=2*3X+2*4X<BR>\n" );
document.write( "490=6X+8X<BR>\n" );
document.write( "490=14X<BR>\n" );
document.write( "X=490/14<BR>\n" );
document.write( "X=35<BR>\n" );
document.write( "3*35=105 FOR THE LENGTH.<BR>\n" );
document.write( "4*35=140 FOR THE WIDTH.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "490=2*105+2*140<BR>\n" );
document.write( "490=210+280<BR>\n" );
document.write( "490=490 </SPAN>\n" );
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