document.write( "Question 718091: the area of a rectangular room is 84sq m. if the breath of the room is 5m less than its length, find the perimeter of the room \n" ); document.write( "
Algebra.Com's Answer #440740 by checkley79(3341)![]() ![]() ![]() You can put this solution on YOUR website! A=84=LW OR W=84/L \n" ); document.write( "P=2L+2W \n" ); document.write( "W=L-5 \n" ); document.write( "84/L=L-5 \n" ); document.write( "L(L-5)=84 \n" ); document.write( "L^2-5L-84=0 \n" ); document.write( "(L-12)(L+7)=0 \n" ); document.write( "L-12=0 \n" ); document.write( "L=12 ANS. FOR THE LENGTH. \n" ); document.write( "W=84/712 \n" ); document.write( "W=7 ANS. FOR THE WIDTH. \n" ); document.write( "PROOF: \n" ); document.write( "84=7*12 \n" ); document.write( "84=84 \n" ); document.write( "P=2*7+2*12 \n" ); document.write( "P=14+24=38 ANS. FOR THE PERIMETER.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |