document.write( "Question 718061: Can you show me the steps on how to do this equation?\r
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document.write( "x/5 = (x-2)/3 \n" );
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Algebra.Com's Answer #440727 by kngt(2)![]() ![]() ![]() You can put this solution on YOUR website! Your question is x/5=(x-2)/3 \n" ); document.write( "Here x/5 is the Left Hand Side (LHS) of your Equation \n" ); document.write( "and (x-2)/3 is the Right Hand Side (RHS) of your Equation.\r \n" ); document.write( "\n" ); document.write( "When 5 goes to the RHS '/5' is converted to '*5' ie, division is converted to multiplication. \n" ); document.write( "Similarly, when 3 goes to the LHS '/3' is converted to '*3'.(Similarly '+' is converted to '-' and '-' is converted to '+') \n" ); document.write( "This method is called cross multiplication. \n" ); document.write( "So the new equation is\r \n" ); document.write( "\n" ); document.write( "3*x = 5*(x-2) \n" ); document.write( "3*x = 5*x - 5*2 (opening the bracket) \n" ); document.write( "3*x - 5*x = -10 (5*x goes to LHS so + sign is converted to - sign) \n" ); document.write( "-2*x = -10 \n" ); document.write( "x = -10/-2 ( a negative no. divided by another negative no. is a positive no.) \n" ); document.write( "x = 5 \n" ); document.write( " \n" ); document.write( " |