document.write( "Question 718061: Can you show me the steps on how to do this equation?\r
\n" ); document.write( "\n" ); document.write( "x/5 = (x-2)/3
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Algebra.Com's Answer #440727 by kngt(2)\"\" \"About 
You can put this solution on YOUR website!
Your question is x/5=(x-2)/3
\n" ); document.write( "Here x/5 is the Left Hand Side (LHS) of your Equation
\n" ); document.write( "and (x-2)/3 is the Right Hand Side (RHS) of your Equation.\r
\n" ); document.write( "\n" ); document.write( "When 5 goes to the RHS '/5' is converted to '*5' ie, division is converted to multiplication.
\n" ); document.write( "Similarly, when 3 goes to the LHS '/3' is converted to '*3'.(Similarly '+' is converted to '-' and '-' is converted to '+')
\n" ); document.write( "This method is called cross multiplication.
\n" ); document.write( "So the new equation is\r
\n" ); document.write( "\n" ); document.write( "3*x = 5*(x-2)
\n" ); document.write( "3*x = 5*x - 5*2 (opening the bracket)
\n" ); document.write( "3*x - 5*x = -10 (5*x goes to LHS so + sign is converted to - sign)
\n" ); document.write( "-2*x = -10
\n" ); document.write( "x = -10/-2 ( a negative no. divided by another negative no. is a positive no.)
\n" ); document.write( "x = 5
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