document.write( "Question 718000: an airplane covers a distance of 750 miles in 2 hours when it flies with the wind and 3 1/3 hours when it flies against the wind.what is the speed of the plane in still air? \n" ); document.write( "
Algebra.Com's Answer #440725 by lwsshak3(11628)\"\" \"About 
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an airplane covers a distance of 750 miles in 2 hours when it flies with the wind and 3 1/3 hours when it flies against the wind.what is the speed of the plane in still air?
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\n" ); document.write( "let x=speed of the plane in still air
\n" ); document.write( "let c=speed of the wind
\n" ); document.write( "(x+c)=speed of the plane with the winds
\n" ); document.write( "(x-c)=speed of the plane against the wind
\n" ); document.write( "speed=distance/travel time
\n" ); document.write( "..
\n" ); document.write( "750/2=x+c
\n" ); document.write( "750/(10/3)=x-c
\n" ); document.write( "..
\n" ); document.write( "750=2x+2c
\n" ); document.write( "2250=10x-10c
\n" ); document.write( "..
\n" ); document.write( "3750=10x+10c
\n" ); document.write( "2250=10x-10c
\n" ); document.write( "6000=20x
\n" ); document.write( "x=300
\n" ); document.write( "2c=750-2x=150
\n" ); document.write( "c=75
\n" ); document.write( "speed of the plane in still air=300 mph
\n" ); document.write( "speed of the wind=75 mph
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