document.write( "Question 715292: use the eccentricity of each hyperbola to find its equation in standard form center(4,1),horizontal transverse axis is 12 and eccentricity 4/3 \n" ); document.write( "

Algebra.Com's Answer #440720 by lwsshak3(11628) $\"\"$ $\"About$

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use the eccentricity of each hyperbola to find its equation in standard form center(4,1),horizontal transverse axis is 12 and eccentricity 4/3
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\n" ); document.write( "Standard form of equation for a hyperbola with horizontal transverse axis:
\n" ); document.write( " $\"%28x-h%29%5E2%2Fa%5E2-%28y-k%29%5E2%2Fb%5E2=1\"$ , (h,k)=(x,y) coordinates of center.
\n" ); document.write( "For given hyperbola:
\n" ); document.write( "center: (4,1)
\n" ); document.write( "length of transverse axis=12=2a
\n" ); document.write( "a=6
\n" ); document.write( "a^2=36
\n" ); document.write( "eccentricity:=4/3=c/a
\n" ); document.write( "c=4a/3=24/3=8
\n" ); document.write( "c^2=64
\n" ); document.write( "c^2=a^2+b^2
\n" ); document.write( "b^2=c^2-a^2=64-36=28
\n" ); document.write( "Equation of given hyperbola:
\n" ); document.write( " $\"%28x-4%29%5E2%2F36-%28y-1%29%5E2%2F28=1\"$ \n" ); document.write( "

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