document.write( "Question 718054: Arturo's age is two years more than four times Allen's age. How old will Allen and Arturo be, three years from now? \n" ); document.write( "
Algebra.Com's Answer #440713 by Menjax(62)\"\" \"About 
You can put this solution on YOUR website!
x=4y+2
\n" ); document.write( "y=(x-2)/4
\n" ); document.write( "Arturo's age will be = (4y+2)-3
\n" ); document.write( "Allens age will be = (x-2)/4 +3
\n" ); document.write( "which simplified is 4y-1 and (x+10)/4
\n" ); document.write( "so Arturo will be one year less than four times Allens age
\n" ); document.write( "amd Allen will be ten fourths more than a quarter of Aerutos age
\n" ); document.write( "
\n" );