document.write( "Question 718054: Arturo's age is two years more than four times Allen's age. How old will Allen and Arturo be, three years from now? \n" ); document.write( "
Algebra.Com's Answer #440713 by Menjax(62)![]() ![]() ![]() You can put this solution on YOUR website! x=4y+2 \n" ); document.write( "y=(x-2)/4 \n" ); document.write( "Arturo's age will be = (4y+2)-3 \n" ); document.write( "Allens age will be = (x-2)/4 +3 \n" ); document.write( "which simplified is 4y-1 and (x+10)/4 \n" ); document.write( "so Arturo will be one year less than four times Allens age \n" ); document.write( "amd Allen will be ten fourths more than a quarter of Aerutos age \n" ); document.write( " |