document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=718042>Question 718042</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The weight of two pieces of baggage is 38 kg. If the weight of one is 7 kg less than twice the weight of the other. What is the weight of each piece of baggage? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #440695 by </B><A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><B>algebrahouse.com(1659)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=algebrahouse.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=440695\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x = one weight<BR>\n" );
document.write( "2x - 7 = other weight {one is 7 less than twice the other}\r<BR>\n" );
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document.write( "x + 2x - 7 = 38 {the combined weight of the two is 38}<BR>\n" );
document.write( "3x - 7 = 38 {combined like terms}<BR>\n" );
document.write( "3x = 45 {added 7 to each side}<BR>\n" );
document.write( "x = 15 {divided each side by  3}<BR>\n" );
document.write( "2x - 7 = 23 {substituted 23, in for x, into 2x - 7}\r<BR>\n" );
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document.write( "15 kg and 23 kg are the weights of each piece<BR>\n" );
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