document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=718027>Question 718027</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the dimension of a rectangle. The area is 238cm^ and the perimeter is 62cm? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #440688 by </B><A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><B>algebrahouse.com(1659)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=algebrahouse.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=440688\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2x + 2y = 62 {perimeter is 2 times width + 2 times length}<BR>\n" );
document.write( "xy = 238 {area is width times length}\r<BR>\n" );
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document.write( "x + y = 31 {divided each side of top equation by 2}<BR>\n" );
document.write( "x = -y + 31 {subtracted y from each side}\r<BR>\n" );
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document.write( "y(-y + 31) = 238 {substituted -y + 31, in for x, into x(y) = 238}<BR>\n" );
document.write( "-y² + 31y = 238 {used distributive property}<BR>\n" );
document.write( "y² - 31y + 238 = 0 {added y² and subtracted 31y from each side}<BR>\n" );
document.write( "(y - 17)(y - 14) = 0 {factored into two binomials}<BR>\n" );
document.write( "y - 17 = 0 or y - 14 = 0 {set each factor equal to 0}<BR>\n" );
document.write( "y = 17 or y = 14 {solved each equation for x}\r<BR>\n" );
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document.write( "width is 14 cm and length is 17 cm<BR>\n" );
document.write( "<br>For more help from me, visit: <a  rel=nofollow HREF= \"http://www.algebrahouse.com/\" target = \"_blank\">www.algebrahouse.com</a><br><br> </SPAN>\n" );
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