document.write( "Question 718010: The product of three consecutive integers is 21 more than the cube of the smallest integer. Find the integers. \n" ); document.write( "
Algebra.Com's Answer #440681 by DrBeeee(684)![]() ![]() ![]() You can put this solution on YOUR website! Let n = first integer \n" ); document.write( "Then the second and third consecutive integers are n+1 and n+2, respectively. \n" ); document.write( "Your problem statement gives us \n" ); document.write( "(1) n*(n+1)*(n+2) = n^3 - 21, agree? \n" ); document.write( "Simplify (1) to get \n" ); document.write( "(2) n*(n^2 +3n +2) = n^3 + 21 or \n" ); document.write( "(3) n^3 + 3n^2 + 2n = n^3 + 21 \n" ); document.write( "The n^3 terms of (3) cancel leaving \n" ); document.write( "(4) 3n^2 + 2n - 21 = 0 \n" ); document.write( "Are you good at factoring? No, use the quadratic factoring equation. \n" ); document.write( "I'm fair enough at factoring to be able to use the basic \"rules\" and get \n" ); document.write( "(5) 3n^2 + 2n -21 = (3n - x)*(n + y), where x*y = 21, try 7*3 and get \n" ); document.write( "(6) 3n^2 + 2n -21 = (3n-7)*(n+3) \n" ); document.write( "If you FOIL the right side of (6) you wili get the left side of (6). \n" ); document.write( "Setting (6) equal to zero you get the two roots of (4) as \n" ); document.write( "(7) n = (7/3,-3). \n" ); document.write( "The first root, 7/3 is not a solution because 7/3 is not an integer. The correct root is \n" ); document.write( "(8) n = -3 \n" ); document.write( "Let's check the value n = -3 with (1). \n" ); document.write( "Is (-3*-2*-1 = (-3)^3 + 21)? \n" ); document.write( "Is (-6 = -27 +21)? \n" ); document.write( "Is (-6 = -6)? Yes \n" ); document.write( "Answer: The three consecutive integers are -3, -2, and -1. \n" ); document.write( " |