document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=717961>Question 717961</A>: <I><SPAN STYLE=\"word-break: break-all;\"> three timesa number added to a second number is 33. the first number added to three times the second number is 19. find the two numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #440605 by </B><A HREF=/tutors/aboutme.mpl?userid=oscargut><B>oscargut(2103)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=oscargut><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=oscargut><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=440605\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> three timesa number added to a second number is 33. the first number added to three times the second number is 19. find the two numbers.\r<BR>\n" );
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document.write( "Let x and y those numbers:\r<BR>\n" );
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document.write( "3x+y = 33\r<BR>\n" );
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document.write( "x+3y = 19\r<BR>\n" );
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document.write( "Then  (multiply by 3 2nd eq)\r<BR>\n" );
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document.write( "3x+y = 33\r<BR>\n" );
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document.write( "3x+9y = 57\r<BR>\n" );
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document.write( "Then  (substracting them)\r<BR>\n" );
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document.write( "-8y = -24\r<BR>\n" );
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document.write( "y = 3\r<BR>\n" );
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document.write( "x = 10\r<BR>\n" );
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document.write( " </SPAN>\n" );
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