document.write( "Question 717863: You run at a rate of 5 miles per hour and your friend runs at a rate of 4 miles per hour. Your friend starts 2 miles farther along the trail than you do. If you both start running at the same time, in how many minutes will you catch your friend? \n" ); document.write( "

Algebra.Com's Answer #440590 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let $\"+t+\"$ = the time in hours from when they both
\n" ); document.write( "start running to when you catch your friend
\n" ); document.write( "Let $\"+d+\"$ = the distance that you have to travel until
\n" ); document.write( "you catch your friend
\n" ); document.write( "-----------------------
\n" ); document.write( "Your equation:
\n" ); document.write( "(1) $\"+d+=+5t+\"$
\n" ); document.write( "Your friend's equation:
\n" ); document.write( "(2) $\"+d+-+2+=+4t+\"$
\n" ); document.write( "----------------
\n" ); document.write( "Substitute (1) into (2)
\n" ); document.write( "(2) $\"+5t+-+2+=+4t+\"$
\n" ); document.write( "(2) $\"+t+=+2+\"$
\n" ); document.write( "In 120 minutes, you will catch your friend
\n" ); document.write( "check:
\n" ); document.write( "(1) $\"+d+=+5t+\"$
\n" ); document.write( "(1) $\"+d+=+5%2A2+\"$
\n" ); document.write( "(1) $\"+d+=+10+\"$ mi
\n" ); document.write( "and
\n" ); document.write( "(2) $\"+d+-+2+=+4t+\"$
\n" ); document.write( "(2) $\"+d+-+2+=+4%2A2+\"$
\n" ); document.write( "(2) $\"+d+=+8+%2B+2+\"$
\n" ); document.write( "(2) $\"+d+=+10+\"$ mi
\n" ); document.write( "OK\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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