document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=63161>Question 63161</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/093979862x/algebrahomeworkh>An Incremental Development</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> help would be appreciated!\r<BR>\n" );
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document.write( "Use substitution to solve \r<BR>\n" );
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document.write( "x + 3y = -3 \r<BR>\n" );
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document.write( "and\r<BR>\n" );
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document.write( "3x - 5y = 19 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #44059 by </B><A HREF=/tutors/aboutme.mpl?userid=jai_kos><B>jai_kos(139)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jai_kos><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=44059\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x + 3y = -3  -->(1)<BR>\n" );
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document.write( "3x - 5y = 19 -->(2)\r<BR>\n" );
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document.write( "Multiply the equation(1) by 3, we get\r<BR>\n" );
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document.write( "3x + 9y = - 9\r<BR>\n" );
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document.write( "3x = - 9y - 9    --->(3)\r<BR>\n" );
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document.write( "Now substitue equation(3) in equation(2), we get\r<BR>\n" );
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document.write( "-9y -9 - 5y = 19\r<BR>\n" );
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document.write( " - 14y = 19 + 9\r<BR>\n" );
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document.write( " -14 y = 28\r<BR>\n" );
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document.write( "  y = 28 /-14 =  -2\r<BR>\n" );
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document.write( "Now substitue for y =-2 in equation(1), we get\r<BR>\n" );
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document.write( "x + 3( -2) = -3\r<BR>\n" );
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document.write( "x -6 = -3\r<BR>\n" );
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document.write( "x = -3 + 6\r<BR>\n" );
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document.write( "x = 3\r<BR>\n" );
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document.write( "Therefore x =3 and y =-2 </SPAN>\n" );
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