document.write( "Question 717837: The product of two consecutive odd integers is 22 less than the square of the greater integer. Write an equation and find the integers. Thank You! \n" ); document.write( "

Algebra.Com's Answer #440574 by algebrahouse.com(1659) $\"\"$ $\"About$

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x = first odd integer
\n" ); document.write( "x + 2 = second odd integer {consecutive odd integers increase by two}\r
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\n" ); document.write( "\n" ); document.write( "x(x + 2) = (x + 2)² - 22 {product of two consecutive odd integers is 22 less than square of greater}
\n" ); document.write( "x² + 2x = (x + 2)(x + 2) - 22 {used distributive property on left, when you square a binomial, multiply it by itself}
\n" ); document.write( "x² + 2x = x² + 4x + 4 - 22 {used foil method on right}
\n" ); document.write( "x² + 2x = x² + 4x - 18 {combined like terms}
\n" ); document.write( "2x = 4x - 18 {subtracted x² from each side}
\n" ); document.write( "-2x = -18 {subtracted 4x from each side}
\n" ); document.write( "x = 9 {divided each side by -2}
\n" ); document.write( "x + 2 = 11 {substituted 9, in for x, into x + 2}\r
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\n" ); document.write( "\n" ); document.write( "9 and 11 are the two consecutive odd integers
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