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document.write( "A man invests part of 17,000 pesos at 8% and the rest at 9%. If the annual income from the 2 investments are equal, how much has he invested at each rate? \n" );
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Algebra.Com's Answer #440549 by checkley79(3341)![]() ![]() ![]() You can put this solution on YOUR website! .08X=.09(17,000-X) \n" ); document.write( ".08X=1,530-.09X \n" ); document.write( ".08X+.09X=1,530 \n" ); document.write( ".17X=1,530 \n" ); document.write( "X=1,530/.17 \n" ); document.write( "X=9,000 AMOUNT INVESTED @ 8%. \n" ); document.write( "17,000-9,000=8,000 AMOUNT INVESTED @ 9%. \n" ); document.write( "PROOF: \n" ); document.write( ".08*9,000=720 INTEREST. \n" ); document.write( ".09*8,000=720 DITTO. \n" ); document.write( " \n" ); document.write( " |