document.write( "Question 717739: Luis and Julia have the same number of coins. Luis only has dimes and Julia has only quaters. If Julia has $1.80 more than luis does, how many coins does each have? \n" ); document.write( "
Algebra.Com's Answer #440515 by DrBeeee(684)![]() ![]() ![]() You can put this solution on YOUR website! Let c = number of coins each has. \n" ); document.write( "Let L = the value of Luis' coins, in cents \n" ); document.write( "Let J = value of Julia's coins, in cents \n" ); document.write( "Then we have \n" ); document.write( "(1) J - L = 180 \n" ); document.write( "where we use 180 cents instead of $1.80. \n" ); document.write( "Since Luis has only dimes, the value of his coins is 10*c, and Julia's quarters are worth 25*c. Put L and J into (1) to get \n" ); document.write( "(2) 25*c - 10*c = 180 or \n" ); document.write( "(3) 15*c = 180 or \n" ); document.write( "(4) c = 12 \n" ); document.write( "Let's check this value using (1). \n" ); document.write( "Is (25*12 - 10*12 = 180)? \n" ); document.write( "Is (300 - 120 = 180)? \n" ); document.write( "Is (180 = 180)? Yes \n" ); document.write( "Answer: Luis and Julia each have 12 coins. \n" ); document.write( " |