document.write( "Question 8027: Hope someone can help me with this.\r
\n" ); document.write( "\n" ); document.write( "The question I have is \"+sqrt%28+1.18+%29+\" BUT there is a \"12\" sitting on top of the tip of the square root (like an index to the square root).\r
\n" ); document.write( "\n" ); document.write( "I know the answer is 1.01389 but I don't know how to get the answer manually or using a calculator.\r
\n" ); document.write( "\n" ); document.write( "Any help would be most appreciated!
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Algebra.Com's Answer #4405 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
If you want to use a calculator for this, then you would enter:
\n" ); document.write( "1.18^(1/12)\r
\n" ); document.write( "\n" ); document.write( "Another way is to use logarithms. I don't know whether or not you are familiar with logarithms, but here it is.\r
\n" ); document.write( "\n" ); document.write( "Let: \"x+=+%281.18%29%5E%281%2F12%29\" Raise both sides to the 12th power.\r
\n" ); document.write( "\n" ); document.write( "\"x%5E12+=+1.18\" Take the log of both sides.\r
\n" ); document.write( "\n" ); document.write( "\"12logx+=+log%281.18%29\" Divide both sides by 12.\r
\n" ); document.write( "\n" ); document.write( "\"logx+=+%28log%281.18%29%29%2F12\" Rewrite in exponential form.\r
\n" ); document.write( "\n" ); document.write( "\"10%5E%28logx%29+=+10%5E%28%28log1.18%29%2F12%29\"\r
\n" ); document.write( "\n" ); document.write( "\"x+=+10%5E%280.00599%29\"\r
\n" ); document.write( "\n" ); document.write( "\"x+=+1.013888\" Round to fifth decimal place.\r
\n" ); document.write( "\n" ); document.write( "\"x+=+1.01389\"
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