document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=717541>Question 717541</A>: <I><SPAN STYLE=\"word-break: break-all;\"> there are 20 litres in the petrol tank of a car. If it is 1/3 full, how many more litres will it hold? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #440487 by </B><A HREF=/tutors/aboutme.mpl?userid=jndarrell><B>jndarrell(58)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jndarrell><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=440487\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The problem tells you that they are dividing the tank into 3 parts. <BR>\n" );
document.write( "Take the 20 Litres and divide by 3.<BR>\n" );
document.write( "20/3= 6.6667 (each part)\r<BR>\n" );
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document.write( "If the tank is already 1/3 full, it has 2/3 parts empty. take the 6.667*2<BR>\n" );
document.write( "=13.333333repeat\r<BR>\n" );
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document.write( "The answer, depending on your instructions on rounding, is 13.3333 Litres (don't forget to report the units!!) </SPAN>\n" );
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